t^2=9.5

Solution for t^2=9.5 equation:

t^2=9.5

We move all terms to the left:

t^2-(9.5)=0

We add all the numbers together, and all the variables

t^2-9.5=0

a = 1; b = 0; c = -9.5;
Δ = b2-4ac
Δ = 02-4·1·(-9.5)
Δ = 38
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{38}}{2*1}=\frac{0-\sqrt{38}}{2}
=-\frac{\sqrt{}}{2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{38}}{2*1}=\frac{0+\sqrt{38}}{2}
=\frac{\sqrt{}}{2}
$